Question

please help me to do question number 9 fast

Answer 1

As AB||CD, 5x + 4x = 180            9x = 180       x= 20        5x = 5(20)=100        3x = 3(20)= 602      4x=4(20)=80 .....…………   angle PQC = angle LPQ( corresponding angles axiom) Angle PQC = 60 Angle RSD +angle RSQ = 180 (linear pair axiom) Angle RSD + 100 = 180 Angle RSD = 180-100 = 80 Angle RSD = 80

Answer 2

hi friend.................

here's your answer................

AB||CD, transversal m cuts them

So, angle RSD Corresponding to angle R = 4x

Now, angle RSQ + angle RSD = 180°

Or, 5x + 4x = 180°
Or, 9x = 180°
Or, x= 20°

So, the value of x is 20°
so, angle P = 3x= 3×20 = 60°
now , AB || CD , transversal l cuts them

so, angle PQC= corresponding to angle P = 60°

and angle RSD = 4x = 4 × 20° = 80°

hope it helps you.........sorry for delay........pls mark as brainliest ☺☺☺☺