the height of parallelogram is one third of its base if the area is 108 CM square find the base and height
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area of parallelogram = height × base
ATQ
if the base is x then
h=(1/3)x
so, x×(1/3)x=108
x×1x/3=108
x^2/3=108
x=√324
x=18cm
so, base=18cm and
height=6cm
ATQ
if the base is x then
h=(1/3)x
so, x×(1/3)x=108
x×1x/3=108
x^2/3=108
x=√324
x=18cm
so, base=18cm and
height=6cm
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