Question

please help me to do this..... anyone..

Answer 1

x+2x+3x+10+4x+5+5x=360°. [Exterior angles sum=360°]
15x+15=360
15x=345
x=345/15=23°
Angles=x=23°
2x=46°
3x+10=69+10=79°
4x+5=92+5=97°
5x=115°
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Answer 2

Given that exterior angles of a pentagon are x°,(2x)°, (3x+10)°, (4x+5)° and (5x)°
We know that sum of all exterior angles of a pentagon is 360°
=>x+2x+3x+10°+4x+5°+5x=360°
=>15x+15°=360°
=>15x=345°
=>x=23°
2x=2(23°)=46°
3x+10°=3(23°)+10°=69°+10°=79°
4x+5°=4(23°)+5°=92°+5°=97°
5x=5(23°)=115°

Therefore the exterior angles are 23°, 46°,79°,97°,115°