Question

Please help me to do this question please​

Answer 1

Step-by-step explanation:

Given=EG_|_(is perpendicular to) ED.

AB।।ED

Construction= draw line BD parallel to ED.

Solve= since EG_|_ED

=angle DEG=90°

since AB।। ED & BD_|_ED

hence, angle ABD=angle ABC+angle CBD

=90°=50°+angleCBD

=angleCBD=90°-50°

=angle CBD=40°

angleABD=angleEDB(corresponding angle)

angle CBD=angleCDB

=angle CDB=40°

Now by ASP of triangle,

angle CBD+angleCDB+x=180°

40°+40°+x=180°

=80°+x=180°

=180°-80°=x

[100°=x]

Hope this have helped u. I have to run horves of my mind and type so fastly, typing numbers and formulas. Please consider my answer and mark brainliest.