Question

Please help me to find the height of the tower..to get a mark as brainliest

Answer 1

Answer:

In∆AED, AE=BC=DE(tan45°=1)

In ∆BCD, tan60°=√3=(8√3+DE)/BC

. . . √3. BC=(8√3+DE)

√3DE–DE=8√3

DE=8√3/(√3–1)

SO, HEIGHT OF TOWER=4√6+8√3m

or 4√3(2+√2)m