Question

Please help me to solve it... I will mark it as a brainleast answer

Answer 1

B +CBD = 90o or B + CBO = 90o

CBO = 90o -B

Similarly, BCO = 90o -C

In OBC, CBO + BCO + BOC = 180o (angle sum of a)

(90o -B) + (90o -C) + BOC = 180o

BOC = B +C +180o - 180o

BOC = (B +C)

BOC = (B +C + A) - A (adding and subtracting A)

BOC = (180o) - (40o) (A = 40o)

BOC = 70o