Math, asked by madhurjyaytchannel, 1 year ago

PLEASE HELP ME TO SOLVE QUESTION NO. 7 PLEASE WRITE IN STEP BY STEP........

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Answers

Answered by Jerryscherry

Answer:

Step-by-step explanation:

Area of quadrilateral ABCD=ar∆ABC+ar∆ACD

Just put the formula of 1/2×b×h in both ∆'s and add the area if any problem plz comment

madhurjyaytchannel: PLEASE GIVE ME FULL ANSWER IT IS URGENT

Jerryscherry: Ok wait

Jerryscherry: {1/2×15×8}+{1/2×6×8}

Jerryscherry: 60+24=84cm^2is the and

Jerryscherry: Ans*

madhurjyaytchannel: THANKS

madhurjyaytchannel: WHERE 15 COMES FROM

Jerryscherry: 15cm is the base of ∆ABC

Jerryscherry: We found it by putting Pythagoras thereom

Jerryscherry: (hypotenuse)^2=(perpendicular)^2+(base)^2

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