PLEASE HELP ME TO SOLVE QUESTION NO. 7 PLEASE WRITE IN STEP BY STEP........
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Step-by-step explanation:
Area of quadrilateral ABCD=ar∆ABC+ar∆ACD
Just put the formula of 1/2×b×h in both ∆'s and add the area if any problem plz comment
madhurjyaytchannel:
PLEASE GIVE ME FULL ANSWER IT IS URGENT
Ok wait
{1/2×15×8}+{1/2×6×8}
60+24=84cm^2is the and
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THANKS
WHERE 15 COMES FROM
15cm is the base of ∆ABC
We found it by putting Pythagoras thereom
(hypotenuse)^2=(perpendicular)^2+(base)^2
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