Question

please help me to solve these ​

Answer 1

Step-by-step explanation:

a) 8p2q

b) 6xyz

c) -14ab

d) 5p

e) p2+15p-10

f) 3a4-3a3-2a2+1

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Answer 2

"a4" was replaced by "a^4". 3 more similar replacement(s).

STEP

1

:

Equation at the end of step 1

((2•(a2))+(3•(a3)))-((4•(a2))+3a4)

STEP

2

:

Equation at the end of step

2

:

((2•(a2))+(3•(a3)))-(22a2+3a4)

STEP

3

:

Equation at the end of step

3

:

((2 • (a2)) + 3a3) - (3a4 + 4a2)

STEP

4

:

Equation at the end of step

4

:

(2a2 + 3a3) - (3a4 + 4a2)

STEP

5

:

STEP

6

:

Pulling out like terms

6.1 Pull out like factors :

-3a4 + 3a3 - 2a2 = -a2 • (3a2 - 3a + 2)

Trying to factor by splitting the middle term

6.2 Factoring 3a2 - 3a + 2

The first term is, 3a2 its coefficient is 3 .

The middle term is, -3a its coefficient is -3 .

The last term, "the constant", is +2

Step-1 : Multiply the coefficient of the first term by the constant 3 • 2 = 6

Step-2 : Find two factors of 6 whose sum equals the coefficient of the middle term, which is -3 .

-6 + -1 = -7

-3 + -2 = -5

-2 + -3 = -5

-1 + -6 = -7

1 + 6 = 7

2 + 3 = 5

3 + 2 = 5

6 + 1 = 7

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Final result :

-a2 • (3a2 - 3a + 2)