please help me to solve these questions
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hello friend....!!
• According to your question we should calculate the average velocity.
•ln the first case it is given that,
distance covered = 50km and speed =45km/hr
• In second case it is given that,
distance = 50km and speed = 90 km/hr
according to case ( 1 ) , the time taken is
V = d / t
implies, t = d / V
t = 50 / 45 = 10 / 9 ------( 1 )
similarly for case ( 2 )
V = d / t
t = d / v
t = 50 / 90 = 10 / 18 = 5 / 9 -----( 2)
the total distance covered
D = 50 + 50 = 100 km
therefore,
the average velocity is
V = 100 / ( 10/9 + 5/9 )
V = 100 / ( 15/9)
V = 100 / ( 5/3)
v = ( 100 x 3 ) / 5
therefore,
V = 20 x 3
v = 60 km / hr.
therefore the average velocity is 60km/hr
_________________________________
Hope it is useful...!!
• According to your question we should calculate the average velocity.
•ln the first case it is given that,
distance covered = 50km and speed =45km/hr
• In second case it is given that,
distance = 50km and speed = 90 km/hr
according to case ( 1 ) , the time taken is
V = d / t
implies, t = d / V
t = 50 / 45 = 10 / 9 ------( 1 )
similarly for case ( 2 )
V = d / t
t = d / v
t = 50 / 90 = 10 / 18 = 5 / 9 -----( 2)
the total distance covered
D = 50 + 50 = 100 km
therefore,
the average velocity is
V = 100 / ( 10/9 + 5/9 )
V = 100 / ( 15/9)
V = 100 / ( 5/3)
v = ( 100 x 3 ) / 5
therefore,
V = 20 x 3
v = 60 km / hr.
therefore the average velocity is 60km/hr
_________________________________
Hope it is useful...!!
shiva198:
very good effort sister!!!!!
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