please help me to solve this
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first take the top most line, i.e, [1/6 + 1/ 12]
= 3/ 12 = 1/4
1/ R = 1/ 4
R = 4 ohm
Resistance of top most line = 4 + 8 = 12 ohm
Now, 1/ 12 + 1/ 12 = 1/ R
2/ 12 = 1/ R
R = 6 ohm
1/ 6 + 1/ 18 = 1/ R
Net resistance of circuit = 18/ 4 ohm = 4.5 ohm
By Ohm's Law
V = IR
24 = I x 18
I = 24/ 18
I = 1.33 A
= 3/ 12 = 1/4
1/ R = 1/ 4
R = 4 ohm
Resistance of top most line = 4 + 8 = 12 ohm
Now, 1/ 12 + 1/ 12 = 1/ R
2/ 12 = 1/ R
R = 6 ohm
1/ 6 + 1/ 18 = 1/ R
Net resistance of circuit = 18/ 4 ohm = 4.5 ohm
By Ohm's Law
V = IR
24 = I x 18
I = 24/ 18
I = 1.33 A
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