Question

Please help me to solve this and no spams please or else the answer will be reported ​

Answer 1

$\huge\mathcal{\underline{\underline{\purple{ANSWER:-}}}}$

☕ {Equation(2) × 2} - Equation(1), we get

→ 2x + 6y - 4z - (2x - y + z) = 22 - 3

→ 2x + 6y - 4z - 2x + y - z = 19

→ 7y - 5z = 19 ----(a)

☕ {Equation(2) × 3} - Equation(3), we get

→ 3x + 9y - 6z - (3x - 2y + 4z) = 33 - 1

→ 3x + 9y - 6z - 3x + 2y - 4z = 32

→ 11y - 10z = 32 ----(b)

☃️ Now, {Equation(a) × 2} - Equation(b), we get

→ 14y - 10z - (11y - 10z) = 38 - 32

→ 14y - 10z - 11y + 10z = 6

→ 3y = 6

→ y = 6/3

→ y = 2

⭐ Putting the value of y in equation (a)

→ 7 × 2 - 5z = 19

→ 14 - 5z = 19

→ - 5z = 19 - 14

→ - 5z = 5

→ z = 5/-5

→ z = -1

⭐ Putting the values of y & z in equation(1)

→ 2x - 2 + (-1) = 3

→ 2x - 2 - 1 = 3

→ 2x - 3 = 3

→ 2x = 3 + 3

→ 2x = 6

→ x = 6/2

→ x = 3

• x = 3

• y = 2

• z = -1

Answer 2

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