Question

please help me to solve this question​

Answer 1

Answer:

Q4. Given that the number divides 101,137 leaving remainder 5 in each case.So we subtract 5 from both the numbers so as to get a number that is perfectly divisible.

HCF of 96,132

132 = 96 × 1 + 36

96 = 36 × 2 + 24

36 = 24 × 2 + 12

24 = 12 × 2 + 0

12 the highest number by which 101,137 can be divided so as to leave remainder 5 in each case.

Q5.

Given that the number when increased by three is divisible by 12,16,18. We should find LCM then subtract three from it to obtain the number.

12 = 2 × 3 × 2

16 = 2 × 2 × 2 × 2

18 = 2 × 3 × 3

LCM = 2 × 3 × 2 × 2 × 2 × 3 = 144

The number is 141