Question

please help me to solve this question​

Answer 1

Answer:

Step-by-step explanation:

given that

sinA/sin(90-A) +cosA/cos(90-A)

sinA/cosA+cosA/sinA                (sin(90-A)=cosA

on taking lcm

sinA.sinA+cosA.cosA/sinA.cosA

sin sqareA+cos squareA/sinAcosA

1/sinAcosA

cosecA.secA                             1/sinA=cosecA and 1/cos A=secA

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