Question

Please help me to solve this question.
I need the correct answers.
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Answer 1

Step-by-step explanation:

First we fill find AR by Pythagoras theorem

${h}^{2} = {height}^{2} + {base}^{2}$

${13}^{2} = {5}^{2} + {base}^{2}$

$169 - 25 = {base}^{2}$

${base}^{2} = \sqrt{144 } = 12m$

FIND THE AREA OF TRIANGLE

$= \frac{1}{2} \times base \: \times height$

$\frac{1}{2} \times 12 \times 5 = {30m}^{2}$

Now we will find area of rectangle ARQP

$12 \times 7 = {84m}^{2}$

Total area of trapazium PQRS

${30m}^{2} + {84m}^{2} = {114m}^{2}$