please help. me............
what would be percentage change in momentum if kinetic energy is doubled????
please help......
Answers
Answered by
1
Let m be mass and v be velocity initially
Now K.E is doubled
As KE is proportional to V^2
So If KE is doubled V becomes √2 times
Now Change in momentum = mv ( √2 - 1)
%, change in momentum = mv ( √2 -1)/ mv. × 100
= ( √ 2 -1) × 100
= 1.4 -1) × 100
= 0.4× 100
= 40% approx
Now K.E is doubled
As KE is proportional to V^2
So If KE is doubled V becomes √2 times
Now Change in momentum = mv ( √2 - 1)
%, change in momentum = mv ( √2 -1)/ mv. × 100
= ( √ 2 -1) × 100
= 1.4 -1) × 100
= 0.4× 100
= 40% approx
guduuu:
thanks a lot
:-)
Answered by
0
Answer:
decrease by 19%
Explanation:
Similar questions