Physics, asked by subhash81, 1 year ago

please help me with question no 21 .It is more than one option correct question. explain on the page

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Answered by Anonymous
1
Here is your answer
______________⤵

Firstly, write equations of motion for both the guns...

gun2 :- fires at t = 0

x direction :-
x =5√3 × cos 60 × (t )   

y direction:-
y =  5√3sin60(t) - 1/2 ×g ×(t)2 

gun1 :- fires at t=t1

x direction :-
x =5√3 ×(t-t1)   

y direction :-
y =  - 1/2 ×g ×(t-t1)2   (negative as upward direction is positive

➡when they collide their x and y cordinates are equal ,

so, if they collide at t=t2 then,

5√3 ×t2-t1= 5√3 × cos 60 × (t2 )   

- 1/2 ×g ×(t2-t1)2  =  5√3sin 60(t2) - 1/2 ×g ×(t2)2 

➡solving we get ,

t2= 2s , t1 =1s

so,

1) time interval b/w firing  =t1 =1s

2)p = (5√3 × (2-1) ,  -1/2×g×(2-1)2 )

p =(5√3)...✔
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