please help me with question no 21 .It is more than one option correct question. explain on the page
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______________⤵
Firstly, write equations of motion for both the guns...
gun2 :- fires at t = 0
x direction :-
x =5√3 × cos 60 × (t )
y direction:-
y = 5√3sin60(t) - 1/2 ×g ×(t)2
gun1 :- fires at t=t1
x direction :-
x =5√3 ×(t-t1)
y direction :-
y = - 1/2 ×g ×(t-t1)2 (negative as upward direction is positive
➡when they collide their x and y cordinates are equal ,
so, if they collide at t=t2 then,
5√3 ×t2-t1= 5√3 × cos 60 × (t2 )
- 1/2 ×g ×(t2-t1)2 = 5√3sin 60(t2) - 1/2 ×g ×(t2)2
➡solving we get ,
t2= 2s , t1 =1s
so,
1) time interval b/w firing =t1 =1s
2)p = (5√3 × (2-1) , -1/2×g×(2-1)2 )
p =(5√3)...✔
______________⤵
Firstly, write equations of motion for both the guns...
gun2 :- fires at t = 0
x direction :-
x =5√3 × cos 60 × (t )
y direction:-
y = 5√3sin60(t) - 1/2 ×g ×(t)2
gun1 :- fires at t=t1
x direction :-
x =5√3 ×(t-t1)
y direction :-
y = - 1/2 ×g ×(t-t1)2 (negative as upward direction is positive
➡when they collide their x and y cordinates are equal ,
so, if they collide at t=t2 then,
5√3 ×t2-t1= 5√3 × cos 60 × (t2 )
- 1/2 ×g ×(t2-t1)2 = 5√3sin 60(t2) - 1/2 ×g ×(t2)2
➡solving we get ,
t2= 2s , t1 =1s
so,
1) time interval b/w firing =t1 =1s
2)p = (5√3 × (2-1) , -1/2×g×(2-1)2 )
p =(5√3)...✔
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