Question

Please help me with question number 9

Answer 1

Required system of equations;

$f( - 2) = - 8a + 4b - 8 = 0 \\ f(2) = 8a + 4b - 4 = 4$

Then,

- 16a - 4 = -4

or, a = 16

Similarly, b = 39

HOPE THIS COULD HELP!!!

Answer 2

Answer:

When you divide $ax^{3} + bx^{2} + x - 6$ by $x + 2$ you get $-8a -4b -8$ as remainder. Setting the remainder equal to zero, you get your first equation as: $-8a -4b -8 = 0$

Next, when you divide $ax^{3} + bx^{2} + x - 6$ by $x - 2$ you get $8a +4b -4$ as remainder. Set this equal to 4, you get the second equation $8a +4b -4 = 4$

On solving the two equations, you get

$a = 0\\b = 2$

Step-by-step explanation: