Question

Please help me with the above question.

I'll give you 10 thanks but please help me.

and if spam then I'll report your 20 answers..​

Answer 1

Answer:

Let P(n) : xn – yn is divisible by x – y, where x and y are any integers with x≠y.

Now, P(l): x1 -y1 = x-y, which is divisible by (x-y)

Hence, P(l) is true.

Let us assume that, P(n) is true for some natural number n = k.

P(k): xk -yk is divisible by (x – y)

or xk-yk = m(x-y),m ∈ N …(i)

Now, we have to prove that P(k + 1) is true.

P(k+l):xk+l-yk+l

= xk-x-xk-y + xk-y-yky

= xk(x-y) +y(xk-yk)

= xk(x – y) + ym(x – y) (using (i))

= (x -y) [xk+ym], which is divisible by (x-y)

Hence, P(k + 1) is true whenever P(k) is true.

So, by the principle of mathematical induction P(n)

is true for any natural number n.

Step-by-step explanation:

i hope you got ur answer and yes I am not here to mark as a brainly I am not lured of that but I do bcoz I like to help someone

Answer 2

Answer:

sissy I didn't came to spam or anything

but I wanted to say that I'm really useless and even if I change my bio here the situations won't change right :( I'm really useless this is the reason why I really hate my life and myself for sure

I don't know why I'm still here

alot of change happened between this month it's kinda waste being alive just totally worthless

and ya don't be sad I didn't came to make you worried

and ya I'm fine as usual :)

like us said I'll change my bio again:D