Math, asked by saptarshi005, 10 months ago

please help me with the question above in the attachment ​

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Answers

Answered by Anonymous
2

{\pink{\underline{\huge{\mathscr{wohooooooooooo}}}}}

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Question ❤

\frac{2^(n+1)+2^n}{2^(n+3)-2^(n+1)}

solution❤

\frac{2^(n+1)+2^n}{2^(n+3)-2^(n+1)}

\frac{2^n*2^1+2^n}{2^n*2^3-2^n*2^1}

\frac{2^n(2+0)}{2^n(2^3-2)}

\frac{2}{8-2}

\frac{2}{6}

\frac{1}{3}

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thank you❤

hope it helps u❤

Answered by InfiniteSoul
6

{\underline{\huge{\mathbf{\color{pink}{Question}}}}}

\dfrac{2^n+2^1 + 2^n}{2^n+2^3 - 2^n+2^1}

{\underline{\huge{\mathbf{\color{pink}{Solution}}}}}

\dfrac{2^n+2^1 + 2^n}{2^n+3 - 2^n+2^1}

 \dfrac{2^n(2^1)}{2^n(2^3 - 2^1)}

 \dfrac{2}{8 - 2}

 \dfrac{2}{6}

 \dfrac{1}{3}

_____________________❤Thank you ❤

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