Question

Please solve it urgently ​

Answer 1

ANSWER

14.4N

Step By Step Explanation

Given,

Let the charge on proton be q and Q respectively where

Q = q =$1.6 \times{10}^{-19}$

And, R = distance between two protons = $4\times {10}^{-15}$m

Now we need to find the force in between them which is given by =>

F = $E \times q$

where,

E =$\dfrac{1} {4\pi\epsilon}$ $\dfrac{Q} {r^2}$

So we get =>

F = $\dfrac{1} {4\pi\epsilon}$$\dfrac{Q\times q} {r^2}$

here,

$\dfrac{1} {4\pi\epsilon}$

=$9 \times 10^9 N {m}^{2} {C}^{-2}$

=>F = $\dfrac{9 \times {10}^{9} \times 1.6 \times {10}^{-19} \times 1.6 \times {10}^{-19} } {(4\times10 ^{-15})^{2} }$

=> F = $\dfrac{9 \times {10}^{9} \times 2.56 \times {10}^{-19-19} } { (4\times10^{-15})^{2} }$

=>F = $\dfrac{23.04\times {10}^{-38+9} } { 16\times10^{-30} }$

=>F = $\dfrac{23.04\times {10}^{-29} } {16\times10^{-30} }$

=> F = $\dfrac{23.04\times {10}^{-29+30} } {16}$

=> F =$1.44 \times 10$

=>F = 14.4N