Physics, asked by Anonymous, 1 year ago

Please solve it urgently ​

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Answered by generalRd
3

ANSWER

14.4N

Step By Step Explanation

Given,

Let the charge on proton be q and Q respectively where

Q = q =1.6 \times{10}^{-19}

And, R = distance between two protons = 4\times {10}^{-15}m

Now we need to find the force in between them which is given by =>

F = E \times q

where,

E =\dfrac{1} {4\pi\epsilon} \dfrac{Q} {r^2}

So we get =>

F = \dfrac{1} {4\pi\epsilon} \dfrac{Q\times q} {r^2}

here,

\dfrac{1} {4\pi\epsilon}

=9 \times 10^9 N {m}^{2} {C}^{-2}

=>F = \dfrac{9 \times {10}^{9} \times 1.6 \times {10}^{-19} \times 1.6 \times {10}^{-19} } {(4\times10 ^{-15})^{2} }

=> F = \dfrac{9 \times {10}^{9} \times 2.56 \times {10}^{-19-19} } { (4\times10^{-15})^{2} }

=>F = \dfrac{23.04\times {10}^{-38+9} } { 16\times10^{-30} }

=>F = \dfrac{23.04\times {10}^{-29} } {16\times10^{-30} }

=> F = \dfrac{23.04\times {10}^{-29+30} } {16}

=> F =1.44 \times 10

=>F = 14.4N

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