Question

Please help me with the question below... I am not sure if it is clear but it is asking to find x and y.

Answer 1

Answer:

$\sqrt[3]{ {a}^{6} {b}^{ - 4} } \\ = {( {a}^{6} {b}^{ - 4} ) }^{1 \div 3 } \\ = ({a}^{6}) ^{1 \div 3} \times ( {b}^{ - 4} ) ^{1 \div 3} \\ = {a}^{2} \times {b}^{ - 4 \div 3} \\ {a}^{x} \times {b}^{2y} = {a}^{2} \times {b}^{ - 4 \div 3} \\ comparing \\ x = 2 \: \: and \: \: 2y = - 4 \div 3 \\ x = 2 \: \: and \: \: y = - 4 \div 3 \times 1 \div 2\\ x = 2 \: \: and \: \: y = - 2 \div 3$

Step-by-step explanation:

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