Please help me with the question.
In the given figure, if AC is the bisector of angle BAD such that AD= 3cm, AB= 3cm and AC= 5cm, then the value of CD+BC is
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Answer:in triangle BAC and DAC
AC = AC
angle B = angle D
angle BAC = angle DAC
by AAS CRITERIA
triangle BAC is congurent to triangle DAC
by CPCT
AD = BC = 3 cm
in triangle ACD
(AC) ^ 2 = ( CD) ^2 + ( AD)^2
(5)^2 = (CD)^2 + ( 3)^2
25-9 = (CD) ^2
CD = √16 = 4 CM
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Step-by-step explanation:
the answer is told so what can i do i am a big noob
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