please help me with this
correct answer will get a brainliest answer. No spams or irrelevant answer for I will report
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Given:
Magnitude of force A= 55 N
Magnitude of force B= 17 N
Magnitude of force C= 8 N
To Find:
Magnitude and direction of resultant force acting on block
Solution:
Let the magnitude of resultant force be F
So, on adding all the forces with appropriate sign, we get
F= 55+17-8
F= 64 N
And the direction of resultant force is same as the direction of forces A and B acting on body
Note: Here direction of forces A and B is taken positive and direction of force C is taken negative.
Hence, the magnitude of resultant force is 64 N and direction of resultant force is same as the direction of forces A and B acting on body.
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