please help me with this ..in detail..Only 3rd one
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let 1st no. = x
so, 2nd no. = x
so, 2nd no. = x
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let the three consecutive natural numbers be n, (n+1) and (n+2) . it is given that the sum of the first and second numbers is 15 more than the third number . n+(n+1)= 15+(n+2) => 2n+1=17+n => 2n-n =17-1 =16=> n=16 . Hope it helps you... Mark me as Brainliest.
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