Please help me with this
Log8=…………
Need answer in form of xlogy
50 points so please help me
Answers
Answered by
1
By using the formula,
logm^n = nlogm
so, log8 can also be written as log2³
log2³ is in the form of formula used so on applying it to the forumula,
log 2³=3log2
X = 3 and Y = 2 as u can see!!
value of log2 = 0.3010
=3 * 0.3010
= 0.9(approx)
logm^n = nlogm
so, log8 can also be written as log2³
log2³ is in the form of formula used so on applying it to the forumula,
log 2³=3log2
X = 3 and Y = 2 as u can see!!
value of log2 = 0.3010
=3 * 0.3010
= 0.9(approx)
HappiestWriter012:
thanks
Answered by
1
Hai friend,
I will try to provide a good answer.
__________________________________________
Here is your answer
Formulas required in computing the above question ➡
1)If a = b^c,
log a =log b^c
2) log b^c =c log b
___________________________________________
Key points :-
Cube of 2 =2*2*2=8
there fore 2^3=8
_________________________________
=Log8
= log 2^3
=3log2
-----------------
There fore the answer is 3 log 2
Considering
x log y = 3 log 2
Then
x = 3
y=2
hope helped!!
please mark it as brainliest If helped you!!!
-All the best
Praneeth
For any more doubts contact me
I will try to provide a good answer.
__________________________________________
Here is your answer
Formulas required in computing the above question ➡
1)If a = b^c,
log a =log b^c
2) log b^c =c log b
___________________________________________
Key points :-
Cube of 2 =2*2*2=8
there fore 2^3=8
_________________________________
=Log8
= log 2^3
=3log2
-----------------
There fore the answer is 3 log 2
Considering
x log y = 3 log 2
Then
x = 3
y=2
hope helped!!
please mark it as brainliest If helped you!!!
-All the best
Praneeth
For any more doubts contact me
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