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5^{ log ( 1/2 base 1/5 )
=5^{log ( 2^-1 base 5^-1 )}
=5^{log(2 base 5 )
=2
log( 4/(√7+√3) base √2 ) + log{ 1/(10+2√21 ) base 1/2
=log{ 4/(√7 +√3) base 2½} +log { (10+2√21) base 2 }
= log{ (4/(√7+√3)² base 2} + log{ (10+2√21 ) base 2 }
=log { 16/(√7²+√3²+2√21) × (10+2√21) base 2 }
=log { 16 base 2 }
= log (2⁴ base 2)
=4
now , add both finding evaluation
2 + 4 = 6 ( answer )
=5^{log ( 2^-1 base 5^-1 )}
=5^{log(2 base 5 )
=2
log( 4/(√7+√3) base √2 ) + log{ 1/(10+2√21 ) base 1/2
=log{ 4/(√7 +√3) base 2½} +log { (10+2√21) base 2 }
= log{ (4/(√7+√3)² base 2} + log{ (10+2√21 ) base 2 }
=log { 16/(√7²+√3²+2√21) × (10+2√21) base 2 }
=log { 16 base 2 }
= log (2⁴ base 2)
=4
now , add both finding evaluation
2 + 4 = 6 ( answer )
Divyankasc:
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