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x^3 - 23x^2 + 142x - 120
x^3 - x^2 - 22x^2 + 22x +120x -120
x^2(x-2) - 22x(x-2) + 120(x-2)
(x-2)(x^2 -22x +120)
Now,
Using the method of splitting the middle term,we get
(x-2)[x^2 -10x -12x +120]
(x-2)[x(x-10) -12(x-10) ]
(x-2)(x-10)(x-12)
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x^3 - x^2 - 22x^2 + 22x +120x -120
x^2(x-2) - 22x(x-2) + 120(x-2)
(x-2)(x^2 -22x +120)
Now,
Using the method of splitting the middle term,we get
(x-2)[x^2 -10x -12x +120]
(x-2)[x(x-10) -12(x-10) ]
(x-2)(x-10)(x-12)
This is your answer
Please mark as brainliest if you liked the solution
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