Question

Please help me with this question ​

Answer 1

Step-by-step explanation:

${ (\sqrt[3]{4}) }^{2x + \frac{1}{2} } = \frac{1}{32}$

${( \sqrt[3]{4}) }^{ \frac{5x}{2} } = \frac{1}{32}$

${( {4}^{ \frac{1}{3} } )}^{ \frac{5x}{2} } = \frac{1}{32}$

${2}^{ \frac{5x}{3} } = {\frac{1}{2}}^{5}$

${2}^{ \frac{5x}{3} } = {2}^{ - 5}$

$\frac{5x}{3} = - 5$

$x = \frac{ - 5 \times 3}{5}$

x = -3