Question

Please help me with this question. Ignore the cut off figure

Answer 1

LC/CA=CM/CB
2x-x+3/2x=2x+3-x+2/2x+3
x+3/2x=x+5/2x+3
(x+3)(2x+3)=2x(x+5)
now find the value of X

Answer 2

In the triangle AND
LM||AB
So,
$\frac{al}{ac} = \frac{bm}{bc} \\ \frac{x - 3}{2x} = \frac{x - 2}{2x + 3} \\ (x - 3)(2x + 3) = (x - 2)(2x) \\ {2x}^{2} + 3x - 6x - 9 = {2x}^{2} - 4x \\ {2x}^{2} - {2x}^{2} = 6x - 3x - 4x + 9 \\ - x + 9 = 0 \\ x = 9$
so value of x is 9