Math, asked by ayonijakatyayn, 10 months ago

Please help me with this question... Person with correct answer will be marked as BRAINLIEST!

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Answered by Megha6209
1

Answer:

In triangle PST and triangle PRQ

Angle P=Angle P (common)

Angle PTS=Angle PQR(corresponding Angle)

∆PST~ ∆PRQ(By AA similarlarity criterion)

According to theorem

Area of ∆PST/Area of ∆PRQ=(PS) square/PR square

Required area=9:49

Step-by-step explanation:

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