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y=2x^2 find dy/dx
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Step-by-step explanation:
The derivative of a function y = f(x) from the first principles is the value of: lim h-->0 [ (f(x + h) - f(x))/h]
Here y = f(x) = 2x^2
lim h-->0 [ (f(x + h) - f(x))/h]
=> lim h-->0 [ (2*(x + h)^2 - 2*x^2)/h]
=> 2*lim h-->0...
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