Math, asked by traj86403, 11 hours ago

Please help me

y=2x^2 find dy/dx

Answers

Answered by nileshbirari1977
0

Step-by-step explanation:

The derivative of a function y = f(x) from the first principles is the value of: lim h-->0 [ (f(x + h) - f(x))/h]

Here y = f(x) = 2x^2

lim h-->0 [ (f(x + h) - f(x))/h]

=> lim h-->0 [ (2*(x + h)^2 - 2*x^2)/h]

=> 2*lim h-->0...

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