Question

please help meeee


In the given figure, AD divides ∠BAC divides in the ratio 1 : 3 and AD = DB. Determine the value of x. ​

Answer 1

Answer:

BAD=X

DAC=3X

BAC+CAE=180

BAC+108=180

BAC=180-108

BAC=72.......(1)

BAC=BAD+DAC

BAC=X+3X (FROM 1:3)

BAC=4X

72=4X FROM.......(1)

X=72/4

X=18

BAD=X=18

DAC=3X=3×18=54

AD=DB

ABD=BAD

ABD=18

PLUS ALL ANGLE OF TRIANGLE ABD IS 180.

SO

ABD+BAD+ADB=180

18+18+ADB=180

ADB=180-18-18

ADB=144

ADB+ADC=180

144+ADC=180

ADC=180-144

ADC=36

PLUS ALL ANGLE OF TRIANGLE ABD IS 180.

SO

ADC+DAC+X=180

36+54+X=180

90+X=180

X=180-90

X=90

SOLVE