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how to solve x + √x = 6/25
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Answered by
4
Hi
I can help you dear
given,
x + √x = 6/25
Let,
√x = b ---------------( 1 )
.°. Equation x + √x = 6/25 can be written as,
b² + b = 6/25
=> 25b² + 25b = 6
=> 25b² + 25b - 6 = 0
=> 25b² + 30b - 5b - 6 = 0
=> 5b ( 5b + 6 ) - 1 ( 5b + 6 )
=> ( 5b - 1 ) ( 5b + 6 )
.°. 5b = 1 ; 5b = - 6
=> b = 1/5 and b = -6/5
.°. when, b = 1/5
√x = 1/5
=> x = 1/25
when, b = -6/5
=> √x = -6/5
=> x = 36/25
.°. Roots are , 36/25 , 1/25
===================================
I can help you dear
given,
x + √x = 6/25
Let,
√x = b ---------------( 1 )
.°. Equation x + √x = 6/25 can be written as,
b² + b = 6/25
=> 25b² + 25b = 6
=> 25b² + 25b - 6 = 0
=> 25b² + 30b - 5b - 6 = 0
=> 5b ( 5b + 6 ) - 1 ( 5b + 6 )
=> ( 5b - 1 ) ( 5b + 6 )
.°. 5b = 1 ; 5b = - 6
=> b = 1/5 and b = -6/5
.°. when, b = 1/5
√x = 1/5
=> x = 1/25
when, b = -6/5
=> √x = -6/5
=> x = 36/25
.°. Roots are , 36/25 , 1/25
===================================
Anonymous:
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Answered by
1
Answer:
HII CUTIEPIE
Given,
x + √x = 6/25
Let,
√x = b ---------------( 1 )
.°. Equation x + √x = 6/25 can be written as,
b² + b = 6/25
=> 25b² + 25b = 6
=> 25b² + 25b - 6 = 0
=> 25b² + 30b - 5b - 6 = 0
=> 5b ( 5b + 6 ) - 1 ( 5b + 6 )
=> ( 5b - 1 ) ( 5b + 6 )
.°. 5b = 1 ; 5b = - 6
=> b = 1/5 and b = -6/5
.°. when, b = 1/5
√x = 1/5
=> x = 1/25
when, b = -6/5
=> √x = -6/5
= x = 36/25
Thus, Roots are , 36/25 , 1/25
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Step-by-step explanation:
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