Question

Please help..

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${\huge {\mathfrak {\pink {Thanks}}}}$ ​

Answer 1

sin ( A+B) = √3/2
A + B = 60 ---------1. ( sin60 = √3/2)
cot (A-B) = 1
A-B = 45 --------2. ( cot 45 = 1 )
Use elimination method from 1 & 2
A + B = 60
A - B = 45
__________
2A = 105
A = 105 / 2 = 52.5
from equation 1
A + B = 60
52.5 + B = 60
B = 60 - 52.5
B = 7.5

Answer 2

Answer:

A = 105/2 and B = 15/2✅

⭕⭕⏭️⏭️⭕⭕

WE HAVE,

sin (A+B)= √3/2

-:sin 60=√3/2

SO ,A +B = 60. ......(1)

AND WE HAVE,

Cot (A- B) =1 -:cot 45=1

so ,. A-B = 45 ........(1)

adding➕ equation (1) and (2)

2A = 60+45

A = 105/2 ☑️

put the value of A in equation (2)

A - B = 45

105- B=

B = 105/2 -45

B = 15/2 ☑️

hope it helps u .