please help please..........?
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9
Numerator:
⇒ sin 23θ - sin 7θ
We know that sinA - sinB = 2 cos(A + B)/2 sin(A - B)/2
⇒ 2 cos(23θ + 7θ)/2 sin(23θ - 7θ)/2
⇒ 2 cos 15θ sin 8θ
Denominator:
⇒ sin 2θ + sin 14θ
We know that sinA + sinB = 2 sin(A + B)/2 cos(A - B)/2
⇒ 2 sin8θ cos6θ
Now,
Numerator/Denominator:
⇒ (sin 23θ - sin 7θ)/(sin 2θ + sin 14θ)
⇒ (2 cos 15θ sin 8θ)/(2 sin 8θ cos 6θ)
⇒ (cos 15θ)/(cos 6θ).
Given : θ = π/21
⇒ cos(15 * π/21)/(cos 6 * π/21)
⇒ cos(5π/7)/cos(2π/7)
⇒ cos(5π)/cos(2π)
We know that cos(90 - θ) = sin θ.
⇒ sin(π/2 - 5π/7)/sin(π/2 - 2π/7)
⇒ sin(-3π/14)/sin(3π/14)
⇒ -sin(3π/14)/sin(3π/14)
⇒ -1.
Therefore, the answer is -1.
Hope it helps!
Answered by
0
Answer is -1 to this question
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