please help question no 6 and 7 both urgently because tommorow in school this will check with the solution
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6,AB=√(-2-2)^2+(2-5)^2=5.
BC=√(4+2)^2+(2-2)^2=6.
AC=√(4-2)^2+(2-5)^2=√13.
The area ΔABC=1/2x |(-2-2)x(2-5)-(4-2)x(2-5)|=9.
BC=√(4+2)^2+(2-2)^2=6.
AC=√(4-2)^2+(2-5)^2=√13.
The area ΔABC=1/2x |(-2-2)x(2-5)-(4-2)x(2-5)|=9.
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