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Answer:
500G HAS MORE K.E
Explanation:
Answered by
1
m(1) = 500g = 0.5kg ; m(2) = 5kg
v(1) = 50m/s ;
v(2) = 18 km/hr = 18(5/18) = 5m/s
K.E (1) = 1/2 × m(1) × (v(1))²
= (0.5)(50)(50)/2
= 625 kgm²/s²
K.E (2) = 1/2 × m(2) × (v(2))²
= (5)(5)(5)/2
= 62.5 kgm²/s²
so, object A has more K.E
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