Question

please help to solve...​

Answer 1

Comparing ΔABC and ΔBAD, we get

∠BAC = ∠ABD ---- (1)

BC = CD ---- (2)

Since ∠DAC = ∠CBD

=> ∠BAC+∠DAC = ∠ABD + ∠CBD [From (1)]

=> ∠BAD = ∠ABC --- (3)

From (1),(2) and (3), we get

ΔABC ≅ ΔBAD, by ASA congruency