Question

please help tomorrow is my exam {(27)-³/9-³}¼​

Answer 1

Answer:

$[{(27)^{-3}/(9)^{-3}]^{1/4} \\\\= [ (3)^{3*(-3)}/(3)^{2*(-3)}]^{1/4}\\ = [ 3^{-9}/3^{-6}]^{1/4} \ \ \\\\= [ 3 ]^{(-9+6)*(1/4)}\\\\=3^{-3/4} \ \ \ \ (Ans.)$