Question

Please help ! Trigonometry question.

Answer 1

Answer:

Hi here's your answer

Step-by-step explanation:

$\frac{1+tan^{2}A }{1+cot^{2} A}$

as $tan^{2} A = \frac{sin^{2}A }{cos^{2}A }$

and $cot^{2} A = \frac{cos^{2}A }{sin^{2}A }$

let substitute the values in the initial equation we get,

$\frac{1+\frac{sin^{2}A }{cos^{2}A } }{1+\frac{cos^{2} A}{sin^{2} A} }$

by solving the above we get,

$\frac{\frac{cos^{2}A+sin^{2}A }{cos^{2} A} }{\frac{sin^{2}A+cos^{2} A }{sin^{2} A} }$

as $sin^{2}A+cos^{2} A=1$

substituting the value in the above equation we get,

$\frac{\frac{1}{cos^{2}A } }{\frac{1}{sin^{2} A} }$

which can be simplified as ,

$\frac{sin^{2} A}{cos^{2} A}$

which is,

$tan^{2}A$

Mark as brainliest if you are satisfied with my answer

Answer 2

Hope it helps!!

Thank you ✌️