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Given:
PQ=10cm, PR=24cm
Let QR be x cm.
In right angled triangle QPR,
(Hypotenuse)2=(Base)2+(Perpendicular)2 [By Pythagoras theorem]
⇒(QR)2=(PQ)2+(PR)2
⇒x2=(10)2+(24)2
⇒x2=100+576=676
⇒x=676=26cm
Thus, the length of QR is 26cm.
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