Math, asked by brainstar07, 12 days ago

please help unable to do please​

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Answered by AngeIianDevil
20

Given:

PQ=10cm, PR=24cm

Let QR be x cm.

In right angled triangle QPR,

(Hypotenuse)2=(Base)2+(Perpendicular)2 [By Pythagoras theorem]

⇒(QR)2=(PQ)2+(PR)2

⇒x2=(10)2+(24)2

⇒x2=100+576=676

⇒x=676=26cm

Thus, the length of QR is 26cm.

Answered by LaRouge
1

Answer:

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Step-by-step explanation:

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