please help urgently needed.....
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let radius of conical vessel r1 is 5cm
height of conical vessel h1 is 24cm
radius of cylindrical vessel be r2
let the water rise upto the height of h2 cm in the cylindrical vessel
volume of water in conical vessel = volume of water in cylindrical vessel
1/3*pie1*r square = pie2*r square*h2
r1 square*h = 3*r2 square*h2
5*5*24 = 3*10*10*h2
h2 = 5*5*24/3*10*10
=2cm
height of conical vessel h1 is 24cm
radius of cylindrical vessel be r2
let the water rise upto the height of h2 cm in the cylindrical vessel
volume of water in conical vessel = volume of water in cylindrical vessel
1/3*pie1*r square = pie2*r square*h2
r1 square*h = 3*r2 square*h2
5*5*24 = 3*10*10*h2
h2 = 5*5*24/3*10*10
=2cm
Answered by
1
Volume of conical vessel = Volume of water raised
1/3pie r²h = pie R²H
1/3×5×5×24 = 10×10 ×H
5×5×8 = 100H
H=5×5×8/100
H= 2 cm...
1/3pie r²h = pie R²H
1/3×5×5×24 = 10×10 ×H
5×5×8 = 100H
H=5×5×8/100
H= 2 cm...
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