Question

Please Help
WILL MARK BRANLIEST

The cost of 3 markers and 2 pencils is $1.80. The cost of 4 markers and 6 pencils is $2.90.


Part A: Define variables that represent this situation.

Part B: Write a system of equations to represent this situation.

Part C: Solve the system of equations you wrote in Part B.

Part D: Interpret the solution in context of the problem.

Answer 1

Step-by-step explanation:

part A

let cost of 1 marker be rs x

cost of 1 pencil=rs y

Part B

3x+2y=1.80 - (1) ×4

4x+6y=2.90 - (2) ×3

part C

12x+8y=7.20

12x+18y=8.70

- - -

-10y= -1.50

y=0.15

putting the value of y in eq (1)

3x+2×0.15=1.80

3x=1.80-0.30

3x=1.5

x=0.5

Part D

cost of a marker=rs 0.5

cost of a pencil=rs 0.15

Answer 2

Step-by-step explanation:

part A:

Let cost of 1 marker be $x.

and cost of 1 pencil be $y.

part B:

3x + 2y = $1.80___(1)

4x + 6y = $2.90___(2)

part C:

by multiplication method,

3x + 2y = $1.80 ×4

4x + 6y = $2.90 ×3

12x + 8y = $7.20

12x + 18y = $8.70

multiplying above equations, we get

-10y = -$1.50

y = -$1.50/-10 = $0.15

putting the value of y in equation (1)

3x + 2(0.15) = 1.80

3x + 0.30 = 1.80

3x = 1.80 - 0.30 = 1.50

x = 1.50/3 = 0.50

part C:

So, cost of 1 marker = $0.15

and cost of 1 pencil = $0.50

hope it will help you and please mark it as brainliest.