CBSE BOARD XII, asked by MA7, 1 year ago

please help with this integration

Attachments:

Answers

Answered by mk4533976pe0b98
1
then later integrate it by parts
Attachments:

mk4533976pe0b98: let ur ias dream come true
MA7: but we know that limit is never reached
mk4533976pe0b98: try try until u reach the sky
MA7: sayonara
mk4533976pe0b98: kk
MA7: did you solve those determinants
MA7: hello????
mk4533976pe0b98: nope
mk4533976pe0b98: i forgot that thing only
mk4533976pe0b98: had some assignments
Answered by SujalSirimilla
0

Answer:

\to \sf \displaystyle \int \sf \dfrac{1}{cosx-sinx} dx

Multiply and divide the numerator by √2.

\to \sf \displaystyle \int \sf \dfrac{1}{\dfrac{\sqrt{2} }{\sqrt{2} }(cosx-sinx)} dx

\to \sf \dfrac{1}{\sqrt{2} }  \displaystyle \int \sf \dfrac{1}{\dfrac{1}{\sqrt{2}}cosx-\dfrac{1}{\sqrt{2}}sinx} dx

⇒ cos(45) = 1/√2, sin(45)=1/√2

\to \sf \dfrac{1}{\sqrt{2} }  \displaystyle \int \sf \dfrac{1}{sin(45^{\circ})cosx-cos(45^{\circ})sinx} dx

⇒ sin(a-b)=sina cosb-sinb cosa

Here, a = 45°, b = x. Using the above Identity,

\to \sf \dfrac{1}{\sqrt{2} }  \displaystyle \int \sf \dfrac{1}{sin(45-x)} dx

\to \sf \dfrac{1}{\sqrt{2} }  \displaystyle \int \sf cosec(45-x) dx

⇒ Substitute 45 - x = t. dx = -dt.

\to \sf \dfrac{-1}{\sqrt{2} }  \displaystyle \int \sf cosec(t) dt

We know that ∫cosec x =

\to \sf \dfrac{-1}{\sqrt{2} }  ( ln|cosec \: t - cot \: t|)

Substitute t back.

Answer:

\to \boxed{\pink{\bf{\dfrac{-1}{\sqrt{2} }  ( ln|cosec \: (45-x) - cot \: (45-x)|)}}}

Similar questions