Question

please helps me.......

Answer 1

I hope you got your answer.
sorry for my handwriting.

Answer 2

heya !!

Initial velocity of the stone,

u = 0m/s
[ since it is dropped from a height ]

Height of the tower, h = 19.6m
Final velocity of the stone, v = ? ( to be calculated)
Acceleration due to gravity, g = 9.8m/s2
Now, for a freely falling body


${v}^{2} - {u}^{2} = 2gh$
Putting the know value in the above equation,

we get
v2-(0m/s2)2 = 2× 9.8m/s2×19.6m
v2 = 19.6m/s2×19.6m
v2 = (19.6m/s)2
v2 = 19.6m/s

so, the final velocity of the stone is 19.6m/s.


GLAD HELP YOU.

It helps you,
thank you☻

@vaibhav246