Question

please hep me with my maths class 9 polynomials.its very urgent! any help is very much appreciated!!!please help!25pts for 3 ans

Answer 1

••hey user •••°
____________________________________

••°here is your answer °•°
----------------------------------
____________________________________

¤¤ Given :-ax^3+4x^3+3x-4 and x^3-4x+a leave the same remainder when divided by x-3

Let p(x)=ax^3+4x^3+3x-4x and
g(x)=x^3-4x+a

buy remainder theorem if f(x) is divided by x-a then the remainder is f(a)

So if p(x) & g(x) are divided by x-3 then the remainder is p(3) & g(3)

According to the question
p(3)=g(3)
put X in both polynomials

a(3)^3+4(3)^2+3(3)-4=(3)^3-4(3)+a
27a+36+9-4=27-12+a
27a+41=15+a
27a-a+41-15=0
26a+26=0
26a=-26
a=-26/26
a=-1 ¤¤
____________________________________
____________________________________
••hence the value of a is -1••
____________________________________
••hope it is satisfactory ••

Answer 2

HELLO......FRIEND!!

THE ANSWER IS HERE,

$a {x}^{3} + 4 {x}^{2} + 3x - 4 \: and \: {x}^{3} - 4x + a \: leaves \: same \: remainder \: when \: divided \: by \: x - 3.$

So, According to remainder theorem ,

=> x-3 =0

=> x=3.

From the question,

$= > \: a ({3})^{3} + 4( {3})^{2} + 3(x) - 4 = {3}^{3} - 4(3) + a$

$= > \: 27a + 36 + 9 - 4 = 27 - 12 + a$

$= > \: 27a + 41 = 15 + a$

$= > 27a - a = \: 15 - 41$

$= > \: 26a = \: - 26$

$= > \: a = \frac{ - 26}{26}$

=> -1.

:-)Hope it helps u.