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find (a-b-c)^3 if ³√a = ³√c + ³√b
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1
. (a+b+c)^3 = ³√a = ³√c + ³√b
2. a^3+b^3+c^3 - 3 a b c = (a+b+c)(a^2+b^2+c^2 - a b - b c - a c)
Also note that (a^2+b^2+c^2-ab-bc-ac)=1/2((a-b)^2+(b-c)^2+(a-c)^2)
anmol6433:
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