please I need help if some one can answer this question
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MN || PQ , AB is transversal
/_H + /_G = 180° [same side interior angle are supplementry]
PH is bisector of /_H
/_1 = /_2. eq 1
PG is bisector of /_G
/_3 = /_4. eq 2
/_H + /_G = 180
/_1 + /_2 + /_3 + /_4 = 180
By eq 1 and 2
/_1 + /_1 + /_3 + /_3 = 180
2(/_1 + /_3) = 180
/_1 + /_3 = 180/2
/_1 + /_3 = 90
In ∆PGH
/_1 + /_GPH + /_3 = 180 [angle sum property of triangle]
90 + /_GPH = 180
/_GPH = 180-90
/_GPH = 90
hence, it's proved
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