Question

please I need help if some one can answer this question

Answer 1

Answer:

MN || PQ , AB is transversal

/_H + /_G = 180° [same side interior angle are supplementry]

PH is bisector of /_H

/_1 = /_2. eq 1

PG is bisector of /_G

/_3 = /_4. eq 2

/_H + /_G = 180

/_1 + /_2 + /_3 + /_4 = 180

By eq 1 and 2

/_1 + /_1 + /_3 + /_3 = 180

2(/_1 + /_3) = 180

/_1 + /_3 = 180/2

/_1 + /_3 = 90

In ∆PGH

/_1 + /_GPH + /_3 = 180 [angle sum property of triangle]

90 + /_GPH = 180

/_GPH = 180-90

/_GPH = 90

hence, it's proved