Question

please if you know how to solve any of these questions please solve it

Answer 1

Answer:

Below are your answers

Step-by-step explanation:

1. let Garima's age be x

Sudha's age=2x ...given

3(x-10) =(2x-10) .....10 years ago

3x-30=2x-10 x=20

x=20 so Garima age=20 years

sudha age =2×20=40 years

2.taking

(x+2)/3-(x-3)/4

taking lcm of 3and4

[4(x+2)-3(x-3)]/12

=(4x+8-3x+9)/12

=(x+17)/12

also

5-(x-1)/2

(10-x+1)/2

(11 -x)/2

now ( x+17)/12=(11-x)/2

cross multiplication

2x+34=132-12x

14x=98 .... x =7

To verify

taking Lhs

(7+2)/3-(7-3)/4=3-1=2

Rhs

5-(7-1)/2=5-3=2

Lhs=Rhs

hence verified

3. a^2+b^2=58 given

a-b=4 given

ab = to find

we know that (a-b)^2=a^2+b^2-2ab

putting given values

4^2=58-2ab 16=58-2ab

42=2ab ab=42/2=21

so ab= 21

------------------------------------------

hope it helps you thanks