please imidiatly answer
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Sum of the roots = c/a = -6
One root = 3 therefore the other = -6-3 = -9.
Product of the roots = -b/a.
= 2k
Therefore,
2k = 3×-9 = -27
k= -27/2.
One root = 3 therefore the other = -6-3 = -9.
Product of the roots = -b/a.
= 2k
Therefore,
2k = 3×-9 = -27
k= -27/2.
Answered by
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Plzz... mark me as brainliest ...
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dheerajgreat:
can we use b2-4ac in this question
yes but it wil be quite lengthyyyy.......
ok
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